Chem 3240 · Lecture 3.1
Start with a traveling wave: \[\Psi(x,t) = Ae^{i(kx-\omega t)}\]
Insert the de Broglie and Planck relations: \[p = \hbar k \qquad E = \hbar\omega\]
Quantum wave function: \[\Psi(x,t)=Ae^{\frac{i}{\hbar}(px-E t)}\]
Time part returns total energy: \[\frac{\partial \Psi}{\partial t} = -\frac{i}{\hbar} E\, \Psi\]
Spatial part returns kinetic energy: \[\frac{\partial^2 \Psi}{\partial x^2} = -\frac{2m(E - V)}{\hbar^2}\, \Psi\]
Combine via \(K = E - V\) to eliminate \(E\).
\[-\frac{\hbar^2}{2m} \frac{\partial^2 \Psi}{\partial x^2} + V(x)\,\Psi = i\hbar \frac{\partial \Psi}{\partial t}\]
Assume \(\Psi(x,t) = \psi(x)\,T(t)\).
Time part is a simple oscillation: \[\Psi(x,t) = \psi(x)\cdot e^{-iEt/\hbar}\]
\[-\frac{\hbar^2}{2m} \frac{\partial^2 \psi}{\partial x^2} + V(x)\,\psi = E\,\psi\]
Classical total energy: \[H(x,p) = \frac{p^2}{2m} + V(x)\]
Quantum Hamiltonian operator: \[\hat{H} = \hat{K} + \hat{V} = -\frac{\hbar^2}{2m} \frac{\partial^2}{\partial x^2} + V(x)\]
The SE in operator form: \[\hat{H}\psi = i\hbar \frac{\partial \psi}{\partial t}\]
Every classical observable has a quantum operator:
| Observable | Classical | Quantum |
|---|---|---|
| Position | \(x\) | \(\hat{x}=x\) |
| Momentum | \(p\) | \(\hat{p}=-i\hbar \frac{\partial}{\partial x}\) |
| Kinetic energy | \(\frac{p^2}{2m}\) | \(\hat{K}=\frac{\hat{p}^2}{2m}\) |
| Total energy | \(H\) | \(\hat{H}=\hat{K}+\hat{V}\) |
The TI-SE is an eigenvalue problem: \[\boxed{\hat{H} \psi_n = E_n \psi_n}\]
Solving a quantum system means finding the eigenfunctions \(\psi_n\) and eigenvalues \(E_n\) of its Hamiltonian: \(\hat{H}\psi_n = E_n \psi_n\).