Chem 3240 · Lecture 3.3
Infinite walls confine the particle:
\[V(x) = \begin{cases} \infty & x = 0 \text{ or } x = L \\ 0 & 0 < x < L \end{cases}\]
Boundary conditions: \[\psi(0) = \psi(L) = 0\]
Inside, only kinetic energy: \[\hat{H} = -\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\]
The eigenvalue problem \(\hat{H}\psi = E\psi\) becomes
\[\psi''(x) = -k^2\psi(x), \qquad k^2 = \frac{2mE}{\hbar^2}\]
General solution: \[\psi(x) = A\cos(kx) + B\sin(kx)\]
The wall condition forces
\[kL = n\pi \quad\Rightarrow\quad k = \frac{n\pi}{L}, \quad n = 1, 2, 3, \dots\]
Energy is quantized: \[E_n = \frac{n^2 h^2}{8mL^2}\]
Confining a wave to a finite space forces discrete energy levels. Atoms, molecules, and solids inherit their quantized levels this way.
Require total probability of \(1\):
\[\int_0^L \psi_n(x)^2\, dx = 1\]
Using \(\sin^2\theta = \tfrac{1}{2}(1-\cos 2\theta)\) gives \(\tfrac{B_n^2}{2}L = 1\), so
\[B_n = \sqrt{\frac{2}{L}}\]
\[\psi_n(x) = \left(\frac{2}{L}\right)^{1/2}\sin\frac{n\pi x}{L}\]
\[E_n = \frac{n^2 h^2}{8mL^2}\]
The lowest state \(n=1\) has nonzero energy:
\[E_1 = \frac{h^2}{8mL^2} \neq 0\]
Smaller box means larger spacing. Quantum effects dominate when a particle is tightly confined.
Pure state (single eigenstate): probability is time-independent
\[|\psi_n(x,t)|^2 = |\psi_n(x)|^2\]
Mixed state (superposition): probability oscillates in time
\[\psi(x,t) = c_1\psi_1 e^{-iE_1 t/\hbar} + c_2\psi_2 e^{-iE_2 t/\hbar}\]
Separable solution \(\psi = X(x)Y(y)Z(z)\):
\[\psi = \sqrt{\frac{8}{abc}}\sin\frac{n_x\pi x}{a}\sin\frac{n_y\pi y}{b}\sin\frac{n_z\pi z}{c}\]
\[E_{n_x,n_y,n_z} = \frac{h^2}{8m}\left(\frac{n_x^2}{a^2} + \frac{n_y^2}{b^2} + \frac{n_z^2}{c^2}\right)\]
Confining a quantum wave to a box quantizes its energy as \(E_n = \frac{n^2 h^2}{8mL^2}\), forbids rest through zero-point energy, and carves the probability into nodes, with symmetry producing degeneracy in higher dimensions.