Chem 3240 · Lecture 4.2
\[F = -kx\]
The minus sign always points toward equilibrium
\[F = -kx\]
\[m\ddot{x} = -kx\]
\[\ddot{x} + \omega^2 x = 0\]
\[x(t) = A\cos(\omega t + \phi)\]
\[\omega = \sqrt{\frac{k}{\mu}}\]
\[E = \frac{p^2}{2m} + \frac{kx^2}{2}\]
\[\ddot{x} = -\left(\frac{1}{m_1} + \frac{1}{m_2}\right)kx = -\frac{k}{\mu}x\]
\[\mu = \frac{m_1 m_2}{m_1 + m_2}\]
\[U(x) = \frac{1}{2}k(x-x_0)^2 + \frac{1}{6}\gamma(x-x_0)^3 + \cdots\]
A restoring force \(F=-kx\) gives sinusoidal motion \(x(t)=A\cos(\omega t+\phi)\) at \(\omega=\sqrt{k/\mu}\). Any bond near its minimum is harmonic, and the parabola is the launching point for the quantum oscillator.