Chem 3240 · Lecture 7.3
The Schrodinger equation is unsolvable for \(N > 1\) electrons.
The culprit: electron, electron repulsion couples every coordinate.
Idea: let each electron feel only the average field of all the others.
A many-body problem becomes many one-electron problems.
\[\Psi(1, 2, \ldots, N) = \frac{1}{\sqrt{N!}} \begin{vmatrix} \psi_1(1) & \psi_2(1) & \cdots & \psi_N(1) \\ \psi_1(2) & \psi_2(2) & \cdots & \psi_N(2) \\ \vdots & \vdots & \ddots & \vdots \\ \psi_1(N) & \psi_2(N) & \cdots & \psi_N(N) \end{vmatrix}\]
\[\hat{F}\,\psi_i = \varepsilon_i\,\psi_i\]
\[\hat{F} = \hat{h} + \sum_{j}\left(\hat{J}_j - \hat{K}_j\right)\]
\(\hat{h}\): kinetic energy plus nuclear attraction.
\(\hat{J}_j\): Coulomb operator, classical electron, electron repulsion.
\(\hat{K}_j\): exchange operator, a purely quantum effect with no classical analogue.

\(\hat{F}\) depends on the very orbitals it determines, so we iterate:

Helium: the simplest closed-shell test.
Each \(1s\) electron moves in the average field of the other.
The two-electron problem splits into two one-electron problems.

One electron feels the bare nuclear attraction…
…screened by the averaged charge cloud of the other.
The net pull is weaker than the bare nucleus: shielding.
\[E_{HF} = \sum_{i}\langle \psi_i | \hat{h} | \psi_i \rangle + \frac{1}{2}\sum_{i,j}\left(J_{ij} - K_{ij}\right)\]
\(J_{ij}\): Coulomb integral, classical repulsion.
\(K_{ij}\): exchange integral, lowers the energy.
The factor \(\tfrac{1}{2}\) removes double counting of each pair.
Strengths
Limits
Hartree-Fock replaces the impossible many-body problem with a self-consistent set of one-electron equations, where each electron moves in the averaged field of all the others. The Slater determinant enforces antisymmetry and captures exchange exactly, but correlation only on average.
Chem 3240 · Quantum Mechanics